150. Evaluate Reverse Polish Notation
Question
You are given an array of strings tokens
that represents an arithmetic expression in a Reverse Polish Notation.
Evaluate the expression. Return an integer that represents the value of the expression.
Note that:
- The valid operators are
'+'
,'-'
,'*'
, and'/'
. - Each operand may be an integer or another expression.
- The division between two integers always truncates toward zero.
- There will not be any division by zero.
- The input represents a valid arithmetic expression in a reverse polish notation.
- The answer and all the intermediate calculations can be represented in a 32-bit integer.
Example 1:
Input: tokens = ["2","1","+","3","*"]
Output: 9
Explanation: ((2 + 1) * 3) = 9
Algorithm
This question is a typical application of stack.
For expression calculation, we have Polish Notation and Reverse Polish Notation.
Normally we will need a stack to store latest calculation results. If we have met the operator, we could get the two operands from stack pop.
Code
class Solution {
public int evalRPN(String[] tokens) {
Stack<Integer> stack = new Stack();
for (int i = 0; i < tokens.length; i++) {
if ("+".equals(tokens[i])) {
stack.push(stack.pop() + stack.pop());
} else if ("-".equals(tokens[i])) {
int num1 = stack.pop();
int num2 = stack.pop();
stack.push(num2 - num1);
} else if ("*".equals(tokens[i])) {
stack.push(stack.pop() * stack.pop());
} else if ("/".equals(tokens[i])) {
int num1 = stack.pop();
int num2 = stack.pop();
stack.push(num2 / num1);
} else {
stack.push(Integer.valueOf(tokens[i]));
}
}
return stack.pop();
}
}